Let `f(x)={(x^(a) , x > 0),(0, x=0):}` .Rolle's theorem is applicable to f for x in[0,1] ,if a :
(A) -2 (B) -1 (C) 0 (D) `(1)/(2)`

If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2

Rolle's theorem is applicable for the function f(x) = |x-1| in [0,2] .

If f(x)=2(x-1)^(2), x in [0,2] then Rolle's theorem satisfies at

prove that the roll's theorem is not applicable for the function f(x)=2+(x-1)^((2)/(3)) in [0,2]

Verify Rolles theorem for function f(x)=x(x-1)^(2) on [0,1]

Let f(x)={[((e^(3x)-1))/(x),,x!=0],[3,,x=0]} then 2f'(0) is

Let f(x)=Max .{x^(2),(1-x)^(2),2x(1-x)}wherexin[0,1] If Rolle's theorem is applicable for f(x) on largestpossible interval [a,b] then the value of 2(a+b+c) when c in[a,b] such that f(c)=0, is

Let Rolle's theorem is applicable for f(x)=x^(3)+ax^(2)+beta x+2 where x in[0,2] and the value of c= (1)/(2) then (a+2 beta) is