The angular displacement of a particle is given by `theta = t^4 +t^3 +t^2 +1` where ‘t’ is time in seconds. Its angular velocity after 2 sec is

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then,the angular acceleration of the particle at t=2 sec is ……. rad s^(-2)

The angular displacement of a particle is given by theta=omega_(0)t+(1)/(2) alpha^(2), "and" alpha are constatnt velocity at time, t=2 sec will be ("in" rad//sec)-

The angular displacement of particle (in radian) is given by theta=t^(2) + t . Calculate angular velocity at t=2 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The displacement of a particle is given by y=(6t^2+3t+4)m , where t is in seconds. Calculate the instantaneous speed of the particle.

The angular displacement at any time t is given by theta(t) = 2t^(3)-6^(2) . The torque on the wheel will be zero at

The displacement of a particle moving in a circular path is given by theta = 3 t^(2) + 0.8 , where theta is in radian and t is in seconds . The angular velocity of the particle at t=3 sec . Is