Let `f(x,y) =0` be the equation of a circle. If `f (0, lamda)=0` has equal roots `lamda=1,1 and f (lamda, 0 ) =0` has roots `lamda =1/5 ,5,` then the radius of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y)=0 be the equation of circle.If f(0,lambda)=0 has equal roots lambda=1,1 and f(lambda,0)=0 has roots lambda=(1)/(5),5 ,then the radius of the circle

Let phi(x,y)=0 be the equation of a circle. If phi(0,lamda)=0 has equal roots lamda=2,2fandphi(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Suppose f(x,y)=0 is the equation of a circle such that f(x,1)=0 has equal roots (each equal to 2) and f(1,x)=0 also has equal roots (each equal to zero). The equation of circle is

f(x, y) = 0 is a circle such that f(0, lambda) = 0 and f(lambda, 0)=0 have equal roots and f(1, 1)= -2 then the radius of the circle is : (A) 4 (B) 8 (C) 2 (D) 1

The equation cos ^(2) x - sin x+lamda = 0, x in (0, pi//2) has roots then value(s) of lamda can be equal to :

If the equation lamdax^(2)+(2lamda-3)y^(2)-4x-1=0 represents a circle, then its radius is