`cos^6A+sin^6A=1-ksin^2(2A)=>k=`

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cos ^ (6) A + sin ^ (6) A = 1-k sin ^ (2) (2A) rArr k =

sin^6A+cos^6A+3sin^2A.cos^2A=

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

sin^(6)A+cos^(6)A+3sin^(2)A cos^(2)A=0 b.1c2d.3

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

Prove the following identities: sin^(6)A+cos^(6)A=1-3sin^(2)A cos^(2)A

cos ^ (6) A + sin ^ (6) A = (1) / (4) (1 + 3cos ^ (2) 2A) cos6A + sin A = (1 + 3cos22A)

cos ^ (6) A-sin ^ (6) A = cos2A (1- (1) / (4) sin ^ (2) 2A)

Prove that: cos^(6)A-sin^(6)A=cos2A(1-(1)/(4)sin^(2)2A)

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta