A particle of mass `2 kg` is projected with a velocity `(6 hat(i) + 8 hat(j))` m/s. Find the magnitude of change in momentum (in kg m/s) when it just touches ground again.

A particle having mass 2 kg is moving with velcoity (2 hat(i) + 3 hat(j))m//s . Find angular momentum of the particle about origin when it is at (1, 1, 0).

A particle of mass 0.020 kg moves along a curve with velocity 5.0 hat(i)+18 hat(k) m//s . After some time, the velocity changes to 9.0 hat(i) + 22 hat(j) m/s due to action of a single force. Find the work done on the particle during this interval of time.

A particle of mass 1 kg is projected upwards with velocity 60 m/s. Another particle of mass 2 kg is just deopper from a certain height. After 2 kg is just of the particles have colliided with ground, match the following [ Take g= 10 m//s^(2) ]

A particle of mass 1 kg is projected upwards with velocity 60 m/s. Another particle of mass 2 kg is just dropped from a certain height. If, after 2 s, when neither of the particles have collided with ground, the value of the velocity of com (in m/s) is _____

A particle of mass 2 kg located at the position (hat i+ hat k) m has a velocity 2(+ hat i- hat j + hat k) m//s . Its angular momentum about z- axis in kg-m^(2)//s is :

The velocity of a particle of mass 2 kg is given by vec(v)=at hat(i)+bt^(2)hat(j) . Find the force acting on the particle.

A particle is projected with initial velocity u = 10 m//s from a point ( 10m, 0m, 0m ) m along z-axis. At the same time , another particle was also projected with velocity v ( hat(i) - hat(j) + hat( k)) m//s from ( 0m, 10m, 0m). It is given that they collide at some point in the space . Then find the value of v. [ vec(g) = 10 m//s^(2) ( - hat(k))]