सिद्ध कीजिए कि ` (sin 3A cos 4A - sin A cos 2A)/(sin 4A sin A + cos 6 A cos A)= tan 2 A.`

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Prove that: (sin3A cos4A-sin Acos2A)/(sin4A sin A+cos6A cos A)=tan2A

(cos 4x sin 3x -cos 2x sin x )/(sin 4x sin x+ cos 6x cos x)= tan 2x

(cos A + sin A )/( cos A - sin A) - (cos A - sin A )/(cos A + sin A ) = 2 tan 2 A.

( sin A + sin 3A + sin 5A + sin 7A)/(cos A + cos 3 A + cos 5 A + cos 7A) = tan 4A.

(cos A + sin A) / (cos A-sin A) - (cos A-sin A) / (cos A + sin A) = 2tan2A

(sin A sin2A + sin3A sin6A) / (sin A cos2A + sin3A cos6A) = tan5A

sin4A = 4sin A cos ^ (3) A-4cos A sin ^ (3) A

Prove that : (cos 4x sin 3x - cos 2x sin x)/(sin 4x .sin x + cos 6x .cos x) = tan 2x

(sin^4A-cos^4A)/(sin^2A-cos^2A)=

Show that sin 3 A + sin 2A -sin A = 4 sin A cos (A)/(2) cos "" (3A)/( 2)