Assertion : If a dipole is enclosed by a surface, then according to Gauss's law, electric flux linked with it will be zero.
Reason : The charge enclosed by a surface is zero.

Give reason : "If net flux assocaited with closec surface is zero, then net charge enclosed b that surface is zero."

An electric dipole is enclosed in a cube, but total electric flux linked will be zero, Discuss.

If a charge is enclosed by the surface of the sphere then total flux emitted from the surface will be:

If a charge is enclosed by the surface of the sphere then total flux emitted from the surface will be:

Assertion: No net charge can exist in the region where electric field is uniform. Reason: For any type of Gaussian surface selected within the region of a uniform electric field, the angle between electric field intensity and area normal is 90^@ everywhere. Hence, electric flux linked with the selected Gaussian surface is equal to zero. If the net electric flux is zero for some Gaussian surface then according to Gauss's law the net charge enclosed within the surface must be zero.

Which of the following statement is correct ? If E = 0 , at all points of a closed surface. a. the electirc flux through the surface is zero. b. the total charge enclosed by the surface is zero.

Which of the following statement is correct ? If E = 0 , at all points of a closed surface. a. the electirc flux through the surface is zero. b. the total charge enclosed by the surface is zero.

Assertion(A):If Gaussian surface does not enclose any charge then vec(E) at any point on the Gaussian surface must be zero. Assertion(R ):No net charge is enclosed by Gaussians surface,so net flux passing through the surface is zero.