When 3.2 gm of sulphur is vapourized at `450^(@)C` and 723 mm pressure, the vapour occupies a volume of 780 m, what is the formula for the sulphur under these conditions?

When 3.2g of sulphur is vapourised at 450^(@)C and 723 mm pressure , the vapours occupy a volume of 780ml. What is the molecular formula of sulphur vapours under these conditions? Calculate the vapour density also.

When 3.2g sulphur is vaporised at 450^(@)C and 723mmHg pressure,the vapours occupy a volume of 780ml what is the molecular formula of S-vapour

When 3.2 g S is vaporized at 450^(@)C and 723 mm pressure, the vapours occupy a volume of 780 mL What is the molecular formula of S vapours ?

At 450^(@)C and 723 mm pressure, 3.2 g of sulphur vapours occupy a volume of 780 mL. What is the molecular formula under these conditions?

State Gay Lussac's lw related to pressure annd temperature of a gas. 3.2g of sulphur when vaporised, the sulphur vapour occupies a volume of 280.2 mL at STP. Determine the molecular formula of sulphur vapour under this condition. (S=32).

State Gay Lussac's law related to pressure and temperature of a gas. 3.2g of sulphur when vaproised the sulphur vapour occupies a volume of 280.2 mL at STP . Determine the molecular formula of sulphur vapour under this condition . (S = 32)

When 3.2gm of sulphur is vapourised,it gives 280ml of vapour at 273^(@)C and 1520mm pressure.Molecular formula of sulphur is

If 3.2 g of sulphur is heated to a temperature, the sulphur vapour produced occupies a volume of 780 mL at 723 mm pressure and 450^(@)C . What is the molecular formula of sulphur at this state?