If a be the first term, l the nth and p the product of first n terms of a G.P. show that, `p^(2) = (al)^(n)`.

If a be the first term, b be the nth term and P be the product of n terms of a GP then prove that P^2=(ab)^n .

5th term of a G.P. is 2, then the product of first 9 terms is:

If the third term of a G.P is P. Then the Product of the first 5 terms of the G.P is

If fifth term of a G.P. is 2, then the product of its first 9 terms is

nth term of a G.P. is a + (n – 1)d.

Fifth term of G.P. is 2. The product of its first nine terms is

The third term of a G.P. is 2. Then product of the first five terms, is :

The third term of a G.P. is 2. Then product of the first five terms, is :

If the nth term of a G.P. be p, then show that the product of its first (2n-1) terms is p^(2n-1) .

If the first and the nth terms of a G.P,are a and b ,respectively,and if P is hte product of the first n terms prove that P^(2)=(ab)^(n).