`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

Cu+y HNO_(3) rarr Cu(NO_(3))_(2) +Z NO + H_(2)O .Then y" and "z" in the balanced chemical equation are respectively "

Cu + HNO_(3) rarr NO + Cu(NO_(3))_(2) + H_(2)O . Write the ionic equation and balance.

From the equation : 3Cu + 8HNO_(3) to 3Cu (NO_(3))_(2) + 4H_(2)O + 2NO Calculate : mass of copper needed to react with 63 g of HNO_(3)

From the equation : 3Cu + 8HNO_(3) to 3Cu (NO_(3))_(2) + 4H_(2)O + 2NO Calculate : volume of nitric oxide at S.T.P. that can be collected.

5Cu + 2HNO_(3)rarr 5CuO + H_(2)O + N_(2) , mark out the correct statement(s)

Cu+X rarr Cu(NO_(3))_(2) + 2H_(2)O + 2NO_(2) . Here X is -

The equation Cu + XHNO_(3) to Cu(NO_(3)) + Y NO_(2) + 2H_(2)O the values of X and Y are

3PbS+8HNO_(3)(Dil.) to 3Pb(NO_(3))_(2)+3S darr+2NO+4H_(2)O