[tan alpha+2tan(2 alpha)+4tan(4 alpha)],[+...+2^(n-1)tan(2^(n-1)alpha)+2^(n)],[cot(2^(n)alpha)" is "]

The value of tanalpha+2tan(2alpha)+4tan(4alpha)+...+2^(n-1)tan(2^(n-1)alpha)+2^(n)cot(2^(n)alpha) is

The value of tan alpha +2tan(2alpha)+4tan(4alpha)+...+2^(n-1)tan(2^(n-1)alpha)+2^ncot(2^nalpha) is

Prove that: tan alpha +2tan 2alpha+ 2^(2)tan 2^(2)alpha +..... + 2^(n-1) tan 2^(n-1)alpha + 2^n cot 2^n alpha=cotalpha .

To find sum of tangents of a series of angles,the angles being in Arithmetical Progression To prove: Explian f his tan alpha+2tan2 alpha+2^(2)tan(2^(2)alpha)+2^(3)tan(2^(3)alpha)+......*2^(n-1)tan(2^(n-1)alpha)+2^(n)cot(2^(n)alpha)=cot alpha given all the functions are defined.

Prove that tan alpha+2 tan 2 alpha+2^(2)tan^(2)alpha+..............+2^(n-1)tan2^(n-1)alpha+2^(@)cot2^(@)alpha=cotalpha

Prove that tan alpha+2 tan 2 alpha+2^(2)tan^(2)alpha+..............+2^(n-1)tan2^(n-1)alpha+2^(@)cot2^(@)alpha=cotalpha

tan alpha+ 2 tan 2 alpha+ 4 tan4 alpha+8 cot 8 alpha=

tan alpha+2tan2 alpha+4tan4 alpha+8cot8 alpha=cot alpha

Given that cot theta-tan theta=2cot2 theta , cot theta+tan theta=2cosec2 theta and cot theta-cot2 theta=cosec2 theta, Tan alpha + 2Tan2 alpha+4Tan4 alpha+.....2^(n)Tan2^(n)alpha=cot alpha-1024cot1024 alpha Then n= a) 10 b) 9 c) 11 d) 8