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" 35."quad " (i) "(x)/(3)-(2)/(x+y)=1qua...

" 35."quad " (i) "(x)/(3)-(2)/(x+y)=1quad " And "quad (x)/(4)+(3)/(x+y)=3

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(4)/(x-y) + (1)/(x + y) = 3 , (2)/(x - y) - (3)/(x + y) = 5

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1/(3x+y)+1/(3x-y)=3/4 and 1/(3x+y)-1/(3x-y)= -1/4