cos 20^(@) cos 40^(@) cos 60^(@) cos 80^...

`cos 20^(@) cos 40^(@) cos 60^(@) cos 80^(@) = (1)/(16)`

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cos 20^(@) cos 40^(@) cos 80^(@)=

cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos 40^(@) + cos 80^(@) + cos 160^(@) =

cos20 ^ (@) cos40 ^ (@) cos60 ^ (@) cos80 ^ (@) - (1) / (16) =

Prove that cos 20^(@)cos40^(@)cos60^(@)cos80^(@)=(1)/(16)

Prove that cos20^(@)cos40^(@)cos60^(@)cos80^(@)=(1)/(16)

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