" (v) "6z^(2)-5z=21

Subtract the second polynomial from the first polynomials and find the degree of the resultant polynomial. h(z) = z^(5) - 6z^(4) +z f(z) = 6z^(2) + 10z-7

If z=3-2i then show that z^(2)-6z+13=0 Hence find the value of z^(4)-4z^(3)+6z^(2)-4z+17

Divide: 5z^(3)-6z^(2)+7z by 2zsqrt(3)a^(4)+2sqrt(3)a^(3)+3a^(2)-6a by 3a

If z = i(i + sqrt(2)) , then value of z^(4) + 4z^(3) + 6z^(2) + 4z is

" If "(z_(2))/(z_(1))" is purely imaginary then "|(6z_(1)-8z_(2))/(4z_(2)+3z_(1))|" is equal to."

If |z|=2 and the locus of 5z-1 is the circle having radius 'a' and z_(1)^(2)+z_(2)^(2)-2z_(1)z_(2)cos theta=0 then |z_(1)|:|z_(2)|=

If z=e^((2pi i)/5) , then 1+z+z^(2)+z^(3)+5z^(4)+4z^(5)+4z^(6)+4z^(7)+4z^(8)+5z^(9)=

If z=e^((2pi i)/5) , then 1+z+z^(2)+z^(3)+5z^(4)+4z^(5)+4z^(6)+4z^(7)+4z^(8)+5z^(9)=

If z=e^((2pi i)/5) , then 1+z+z^(2)+z^(3)+5z^(4)+4z^(5)+4z^(6)+4z^(7)+4z^(8)+5z^(9)=

If z_(0), z_(1),z_(2),...,z_(5) be 6^(th) roots of unity where z_(0)=1 then the value of (1)/(3)(2+z_(1))(2+z_(2))...(2+z_(5)) is...