" (ix) "((x)/(a))^(2/3)+((y)/(b))^(2/3)=1quad " at "(a cos^(3)theta,b sin^(3)theta)

Find the equations of tangent and normal to the curve ((x)/(a))^((2//3))+((y)/(b))^(2//3)=1 at (a cos^(3) theta, b sin^(3), theta)

If x=a cos^(3)theta,y=b sin^(3)theta, then

Find the equations to the tangents and normals to the following curves at the indicated points. (x/a)^2/3 +(y/b) 2/3 = 1 at (a cos^3 theta, b sin^3 theta)

If x = a cos^3 theta, y = b sin^3 theta , then

Find the blanks. (i) If x=a cos^(3)theta,y=b sin^(3)theta then ((x)/(a))^(2/3)+((y)/(b))^(2/3)=ul(P) (ii) if x=a sec theta cos phi,y=b sec theta sin phi and z=c tan theta then (x^(2))/(a^(2))+(y^(2))/(b^(2))-(z^(2))/(c^(2))=ul(Q) (iii) If cos A+cos^(2)A=1 ,then sin^(2)A+sin^(4)A=ul(R)

Find (d^2 y)/(dx^2) of the following: x = a cos^3 theta , y= b sin^3 theta

If x = (sin^(3)theta)/(cos^(2) theta)and y = (cos^(3) theta)/(sin^(2)theta) , where sin theta + cos theta = (1)/(2) , " then " x + y =

If (ax)/(cos theta)+(by)/(sin theta)=a^(2)-b^(2)(ax sin theta)/(cos^(2)theta)-(by cos theta)/(sin^(2)theta)=0then(ax)^((2)/(3))+(by)^((2)/(3))=