`(tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)` is equal to

(sintheta)/(1-cottheta)+(costheta)/(1-tantheta) is equal to (a) 0 (b) 1 (c) sintheta+costheta (d) sintheta-costheta

sintheta/(1-cottheta)+costheta/(1-tantheta)=

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (iii) (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+sectheta cosectheta

Prove that : (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+sectheta" cosec "theta

Prove that: (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+secthetacos e ctheta

Prove the following identities, where the angles involved are acute angles for which the expressions are defined. : (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+secthetacosectheta .

Prove the following identities,where the angles involved are acute angles for which the expressions are defined. (iii) (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+secthetacosectheta

Prove the following identities. where the angles involved are acute angles for which the expressions are defined. (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+secthetacosectheta [ Hint: Write the expression in terms of sin theta and cos theta ]

Prove: (tantheta)/(1- cottheta)+(cottheta)/(1-tantheta)=1+tantheta+cottheta

Prove that: (tantheta)/(1-cottheta)+(cottheta)/(1-tantheta)=1+tantheta+cottheta