[" 2."sin(B+C-A)+sin(C+A-B)],[+sin(A+B-C)=4sin A sin B sin C*x]

If A + B + C =180^@ , prove that : sin (B+C-A) + sin(C+ A-B)+ sin(A +B-C)=4sin A sinB sinC .

In triangle ABC, prove that sin(B+C-A)+sin(C+A-B)+sin(A+B-C)=4sin A sin B sin C .

sin (B + CA) + sin (C + AC) + sin (A + BC) = 4sin A sin B sin C

If A + B + C = 180^(@) , prove that sin(B + C - A) + sin (C + A - B) + sin(A + B + C) = 4 sin A sin B sin C.

Theorem 1:sin2A+sin2B+sin2C=4sin A sin B sin C

In any triangle ABC,sin^(2)A-sin^(2)B+sin^(2)C is always equal to (A) 2sin A sin B cos C(B)2sin A cos B sin C(C)2sin A cos B cos C(D)2sin A sin B sin C

sin (A+B+C)+sin(A-B-C)+sin(A+B-C)+sin(A-B+C)=

If A+B+C=0 , then prove that sin 2A + sin 2B+ sin 2C=-4sin A sin B sin C .

Show that: sin A + sin B +sin C - sin(A+B+C)=4 sin ((A+B)/2)sin ((B+C)/2)sin ((C+A)/2)

Simplify: sin (B + C) sin (B - C) + sin (C + A) sin (C - A) + sin(A + B) sin (A - B)