[x+(6)/(y)=6],[3x-(8)/(y)=5quad (y!=0)]...

[x+(6)/(y)=6],[3x-(8)/(y)=5quad (y!=0)]

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x+(6)/(y)=6,3x-(8)/(y)=5 then y=………

x + ( 6) /( y ) = 6, 3x - ( 8)/( y) = 5 ( y ne 0 )

Solvex + (6) / (y) = 6.3x- (8) / (y) = 5

Solve each pair of equation by using the substitution method. x+(6)/(y)=6 and 3x-(8)/(y)=5 .

solve for x and y, x+ (6/y)=6,3x-(8/y)=5

2x+5y=8/3, 3x-2y=5/6

The circles x^(2)+y^(2)-6x-8y=0 and x^(2)+y^(2)-6x+8=0 are

6x-3y=-10,3x+5y-8=0

Find x and y, if {:[(1,6),(0,x)] + [(y,0),(1,2)] = [(5,6),(1,8)]

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