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If n=1,2,3,……. then cos alpha cos 2 ...

If `n=1,2,3,…….` then ` cos alpha cos 2 alpha cos 4 alpha ……. Cos 2^(n-1) alpha` is equal to

A

`(sin 2 n alpha )/( 2n sin alpha )`

B

`(sin 2^n alpha )/( 2^n sin 2 ^(n-1) alpha)`

C

`(sin 4^(n-1) alpha)/( 4^(n-1) sin alpha )`

D

`(sin 2^n alpha)/(2^n sin alpha `

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The correct Answer is:
D
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