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for any angle theta the expression ...

for any angle ` theta ` the expression ` (2 cos 8 theta + 1)/( 2 cos theta +1)` is equal to

A

` ( 2 cos theta +1) ( 2 cos 2 theta +1) ( 2 cos 4 theta + 1)`

B

`(cos theta -1) ( cos 2 theta -1) ( cos 4 theta -1)`

C

`(2 cos theta-1) ( 2 cos theta -1) (2 cos 4 theta -1)`

D

`(2 cos theta +1) (2 cos 2 theta +1) ( 2 cos 4 theta +1)`

Text Solution

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The correct Answer is:
C
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