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If |z1|=|z2|=|z3|"…."=|zn|=1 then |z(1)+...

If `|z_1|=|z_2|=|z_3|"…."=|z_n|=1` then `|z_(1)+z_(2)+"….."+z_(n)|=`

A

`|z_(1)z_(2)z_(3)"………."z_(n)|`

B

`(1)/(|z_(1)z_(2)"………"z_(n)|)`

C

`|(1)/(z_(1))+(1)/(z_(2))+"………"+(1)/(z_(n))|`

D

`|(1)/(z_(1)z_(2))+(1)/(z_(2)z_(3))+"………"(+1)/(z_(n-1)z_(n))|`

Text Solution

Verified by Experts

The correct Answer is:
C
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