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((cos theta+isin theta)^4)/((sin theta+i...

`((cos theta+isin theta)^4)/((sin theta+icos theta)^5)=?`

A

`cos theta-isin theta`

B

`sin theta- icos theta`

C

`cos 9theta - isin 9theta`

D

`sin 9theta - icos 9theta`

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The correct Answer is:
D
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