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If roots `alpha, beta` of the equation `(x^(2)-bx)/(ax-c)=(lambda-1)/(lambda+1)` are such that `alpha+ beta=0`, then the value of `lambda` is

A

`(a-b)/(a+b)`

B

`c`

C

`(1)/(c )`

D

`(1)/(ab)`

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The correct Answer is:
A
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