Mole fraction of `C_(3)H_(5)(OH)_(3)` in a solution of `36g` of water and `46g` of glycerine is:

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine is :

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine is :

Calculate the mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine.

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The mole fraction of glycerine C_(3)H_(5)(OH)_(3) in a solution containing 36 g of water and 46 g of glycerine is :

Mole fraction of glycerine C_3H_5(OH)_3 in solution containing 36 g of water and 46 g of glycerine is

Mole fraction of glycerine (mol,wt=92)" in a solution containing 36g of H_(2)O and 46g of glycerine is "

Calculate the mole fraction of Ethanol (C_(2)H_(5)OH) in the solution containing 20 g of Ethanol and 100 g of water.

The mole fraction of water in a solution containing 50 g of water and 50 g of ethyl alcohol is: