" (1) "(2)/(9),(2)/(3),(8)/(21)quad " (ii) "(1)/(5),(3)/(7),(7)/(10)

Arrange the following in descending order : (i) (2)/(9),(2)/(3),(8)/(21) (ii) (1)/(5),(3)/(7),(7)/(10)

Re-arrange suitably and find the sum in each of the following: (2)/(3)+(-4)/(5)+(1)/(3)+(2)/(5) (ii) (1)/(8)+(5)/(12)+(2)/(7)+(7)/(12)+(9)/(7)+(-5)/(16)

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

Verify the following: (i) (-12)/(5)+(2)/(7)=(2)/(7)+(-12)/(5) (ii) (-5)/(8)+(-9)/(13)= (-9)/(13)+(-5)/(8) (iii) 3+(-7)/(12)=(-7)/(12)+3 (iv) (2)/(-7)+(12)/(-35)=(12)/(-35)+(2)/(-7)

Solve (i) 2-(3)/(5)(ii)4+(7)/(8)(iii)(3)/(5)+(2)/(7)(iv)(9)/(11)-(4)/(5)(v)(7)/(10)+(2)/(5)+(3)/(2)(vi)(2)(2)/(3)+(3)(1)/(2) (vii) (8)(1)/(2)-(3)(5)/(8)

Simplify : [ ((- 3 )/( 2) xx (4)/(5) ) + ((9)/(5) xx (-10)/( 3)) - ((1)/(2)xx (3)/(4)) ] div [ ((21)/( 9) xx (3)/(7)) +((7)/(8) xx (16)/(14)) ]