It takes 10 in for an electric kettle to theat a certain quantity of water from `0^@C` to `100^@C`. It takes 54 min to convert this water `100^@C` into steam Then latent heat of steam is

It takes 10 min for an electric kettle to heat a certain quantity of water from 0^@C to 100^@C . It takes 54 min to convert this water 100^@C into steam Then latent heat of steam is

An electric kettle takes 20 min. to heat a certain quantity of water from 0^@C to boiling point. It requires 90 minutes to turn all the water at 100^@C into steam. Find the latest heat of vaporisation. (specific heat of water= 1 cal//gm//^@C )

An electric heater takes 15 min to raise a certain quantity of water from 0°C to its boiling point.If it takes another 80 min to turn all water into steam ,find the latent heat of vaporsation of water.

An experiment takes 10 minutes to raise temperature of water from 0^(@)C to 100^(@)C and another 55 minutes to convert it totally into steam by a stabilized heater. The latent heat of vaporization comes out to be -

The time taken to heat certain amount of water from 0^@C to 100^@C in an electric kettle is 15 min and to evaporate it completely is 80 mins. Calculate the value of latent heat of .vapourisation?