" (i) "[8^(-3)times2^((1)/(2))times25^((5)/(4))]-:[32^(-(2)/(3))times125^((3)/(6))]=sqrt(2)

[8^(-2/3)times2^(1/2)times25^(-5/4)]÷[32^(-2/5)times125^(-5/6)] =sqrt2

Prove that . (i) [8^(-(2)/(3)) xx 2^((1)/(2))xx 25^(-(5)/(4))] div[32^(-(2)/(5)) xx 125 ^(-(5)/(6)) ] = sqrt(2) (ii) ((64)/(125))^(-(2)/(3)) = (1)/(((256)/(625))^((1)/(4)))+ (sqrt(25))/(root3(64)) = (65)/(16) (iii) [7{(81)^((1)/(4)) +(256)^((1)/(4))}^((1)/(4))]^(4) = 16807 .

(1) (4)/((216)^((2)/(3)))+(1)/((256)^((3)/(4)))+(2)/((243)^((1)/(5))) (ii) ((64)/(125))^((2)/(3))+((256)/(625))^((1)/(4))+((3)/(7))^(0) (iii) ((81)/(16))^((3)/(4))(((25)/(9))^((3)/(2))-:((5)/(2))^(-3)) (iv) ((25)^((5)/(2))times(729)^((1)/(3)))/((125)^((2)/(3))times(27)^((2)/(3))times8^((4)/(3)))

Evaluale (((9)/(4))^((-3)/(2))times((125)/(27))^((-2)/(3))times((3)/(5))^(-3))/((sqrt(2))^(4))

(4)/(5)times((-2)/(3))-(2)/(5)times(1)/(3)+(3)/(5)times(4)/(5)=

(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

(((-2)/(3))^(-2))^(3)times((1)/(3))^(-4)times3^(-1)times(1)/(6)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

(2^(2)times3^(4)times4)/(3times32),

(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)