[1" mole of "N_(2)" and "3" moles of "H_(2)" are placed in "1L" vessel.Find the concentration of "NH_(3)" at equilibrium,if equilibrium "],[" pressure is "1" atm and the equilibrium constant at "400K" is "(4)/(27)]

1 "mole of" N_(2) and 3 "moles of " H_(2) are placed in 1L vessel. Find the concentration of NH_(3) at equilibrium, if the equilibrium constant (K_(c)) at 400K "is" (4)/(27)

1 "mole of" N_(2) "and" 3 "moles of " H_(2) are placed in 1L vessel. Find the concentration of NH_(3) at equilibrium, if the equilibrium constant (K_(c)) at 400K "is" (4)/(27)

1 mole of N_(2) and 3 mole of H_(2) are mixed in a closed vessel of 1 dm^(3) capacity. At equilibrium if the vessel contains a total of 2.4 moles, calculate equilibrium constant K_(c)" for "N_(2)+3H_(2)hArr2NH_(3) .

A mixture of 2 moles of N_(2) and 8 moles of H_(2) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 04 moles of N_(2) was present. The equilibrium concentration of H_(2) will be

A mixture of 2 moles of N_(2) and 8 moles of H_(2) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 04 moles of N_(2) was present. The equilibrium concentration of H_(2) will be

A mixture of 1 mole of N_(2) and 3 moles of H_(2) is allowed to react at a constant pressure of 100 bar. At equilibrium, 0.6 mole of ammonia is formed. Calculate the equilibrium constant for the reaction N_(2)+3H_(2)hArr2NH_(3) .

When 1 mole of N_2 and 1 mole of H_2 is enclosed in 3L vessel and the reaction is allowed to attain equilibrium , it is found that at equilibrium there is 'x' mole of H_2 . The number of moles of NH_3 formed would be

When 1 mole of N_2 and 1 mole of H_2 is enclosed in 3L vessel and the reaction is allowed to attain equilibrium , it is found that at equilibrium there is 'x' mole of H_2 . The number of moles of NH_3 formed would be