`Cl_(2)+H_(2)S to 2HCl+S`,
In that above reaction oxidation state of chlorine changes from

(A) Reaction of Cl_(2) with hot and concen -trated NaOH is disproportionation reaction (R ) Oxidation state of chlorine changed from 0"to"-1and+5

In the chemical reaction Cl_(2)+H_(2)S rarr 2HCl + S , the oxidation number of sulphur changes from

When Cl^(-) ions are converted to Cl_(2) , the oxidation number of chlorine changes from

In the reaction : Cl_(2)+H_(2)S to 2HCl+S , the oxidation number of S changes from

4HCl + A to MnCl_2 + Cl_2 uarr + 2H_2O , In this reaction the change in oxidation state of metal present in A is

With reference to the equation Cl_(2)+H_(2)Sto2HCl+S pertaining to a redox reaction - select the correct answer in each case a. Chlorine is oxidised/reduced to HCl. B. Hydrogen sulphide is oxidised /reduced to sulphur since the reaction involves addition/ removal of hydrogen. c. Chlorine acts as an oxidising / reducing agent.

Consider the equation H_2 + Cl_2 rarr 2HCl What changes takes place in the oxidation number of chlorine ?

Assertion :- H_(2)S+Cl_(2)rarr2HCl+S In the above reaction, Cl has been oxidised to Cl^(-) while S^(-2) has been reduced to S Reason :- In a reaction the element whose oxidation number decreases is reduced and the element whose oxidation number increases is oxidised

Assertion :- H_(2)S+Cl_(2)rarr2HCl+S In the above reaction, Cl has been oxidised to Cl^(-) while S^(-2) has been reduced to S Reason :- In a reaction the element whose oxidation number decreases is reduced and the element whose oxidation number increases is oxidised