" (e) "NO_(2)" readily forms a dimer."

Explain the following : (i) NO_(2) readily forms a dimer. (ii) BiCl_(3) is more stable than BiCl_(5) .

Explain the following : (a) NO_(2) readily forms a dimer. (b) BiCI_(3) is more stable than BiCI_(5).

Explain the following : (a) NO_(2) readily forms a dimer. (b) BiCI_(3) is more stable than BiCI_(5).

Account for the following : (i) Oxygen does not show an oxidation state of + 4 and + 6 like sulfur . (ii) NO_2 readily forms a dimer. (iii) Fluorine always exhibits and oxidation state of -1 only in its compunds

NO_2 readily forms a dimer. Explain.

Which forms dimer ?

Explain why NO_(2) forms dimer .

Assertion : NO_(2) is readily dimerised to N_(2)O_(4) Reason : NO_(2) has one unpaired electron and two such electron with opposite spin in two NO_(2) molecules form bond between two N-atoms readily.