[" If "alpha,beta" are the roots of "x^(2)+ax-b=0" and "],[gamma,delta" are the roots of "x^(2)+ax-b=0" then "],[(alpha-gamma)(alpha-delta)(beta-delta)(beta-gamma)=]

If alpha,beta are the roots of x^(2)+ax-b=0 and gamma,delta are the roots of x^(2)+ax+b=0 then (alpha-gamma)(alpha-delta)(beta-gamma)(beta-delta)=

If alpha,beta be the roots of x^(2)+x+2=0 and gamma, delta be the roots of x^(2)+3 x+4=0 then (alpha+gamma)(alpha+delta)(beta+gamma)(beta+delta)=

If alpha,beta are the roots of x^2+p x+q=0 and gamma,delta are the roots of x^2+p x+r=0, then ((alpha-gamma)(alpha-delta))/((beta-gamma)(beta-delta))= (a) \ 1 (b) \ q (c) \ r (d) \ q+r

If alpha,beta are the roots of x^(2)+px+q=0and gamma,delta are the roots of x^(2)+px+r=0, then ((alpha-gamma)(alpha-delta))/((beta-gamma)(beta-delta))= a.1b.q c.r d.q+r

If alpha, beta be the roots of x^(2)+x+2=0 and gamma, delta be the roots of x^(2)+3 x+4=0 , then (alpha+gamma)(alpha+delta)(beta+gamma)(beta+delta) is equal to

If alpha , beta are the roots of x^2 +px -q=0 and gamma , delta are the roots of x^2 +px+r=0 then (alpha - gamma ) ( beta - gamma) ( alpha - delta ) ( beta- delta )=

If alpha,beta are the roots of x^(2)+px+q=0and gamma,delta are the roots of x^(2)+rx+s=0, evaluate (alpha-gamma)(alpha-delta)(beta-gamma)(beta-delta) in terms of p,q,r, ands.Deduce the condition that the equation has a common root.

If alpha , beta are the roots of x^2 + px +1=0 and gamma , delta are the roots of x^2 +qx +1=0 then (alpha - gamma )(beta - gamma)(alpha + delta )( beta + delta )=