The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed as shown in Figure. Show that `ar(||^(gm) ABCD)=ar (||^(gm) PBQR)`

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A and parallel to C P meets C B produced at Q and then parallelogram P B Q R is completed as shown in Figure. Show that a r(^(gm)A B C D)=a r ^(gm)P B Q R)dot

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A and parallel to C P meets C B produced at Q and then parallelogram P B Q R is completed as shown in Figure. Show that a r(^(gm)A B C D)=a r ^(gm)P B Q R)dot

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed . Show that ar (ABCD) = ar (PBQR)

The sides AB of parallelogram ABCD produced to any point P. A line through A and parallel to CP meets CB produced at Q and the parallelogram PBQR is completed Show that ar(ABCD) = ar(PBQR)

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that a r" "(A B C D)" "=" "a r" "(P B Q R)dot

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that a r\ (A B C D)\ =\ a r\ (P B Q R) .

The side AB of a parallelogram ABCD is produced to any point E. A line through A and parallel to CE meets CB produced at G and then parallelogram EBGF is completed (see the figure). Prove that area of ||gm ABCD = " area of "||gm BEFG .

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A parallel to C P meets C B produced in Q and the parallelogram P B Q R completed. Show that a r(^(gm)A B C D)=a r(^(gm)B P R Q)dot CONSTRUCTION : Join A C and PQ. TO PROVE : a r(^(gm)A B C D)=a r(^(gm)B P R Q)

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A parallel to C P meets C B produced in Q and the parallelogram P B Q R completed. Show that a r(^(gm)A B C D)=a r(^(gm)B P R Q)dot CONSTRUCTION : Join A C and PQ. TO PROVE : a r(^(gm)A B C D)=a r(^(gm)B P R Q)

ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that: ar(ACB) = ar(ACF)