A force `F = - 10x + 2` acts on a particle of mass `0.1 kg` where x is in m and F in newton. If is released from rest at `x = 0`, find:
a. Amplitude:
b. Time period:
c. Equation of motion.

A force F=20+10y acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from y=0 to y=1 m is:

A force F=20+10y acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from y=0 to y=1 m is:

A particle is moving on y axis under a varible force F= - ky + C . If in part (a) F= - 10y + 20 , and mass m of the particle is 2.5kg and it is released from rest from y = +3 , at t= 0, write the equation of SHM.

A particle of mass 0.1 kg is subjected to a force F which varies with distance x as shown. If it starts its journey from rest at x = 0, then its speed at X = 12 m is

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in meter. Find the work done by this force during a displacement from 1. 0 m to x = 2.0 m.

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter. Find the work done by this force during a displacement form x=0 to x=2.0m

A force F=(15+0.50x) acts on a particle in the X-direction ,where F is in newton and x in metre Find the work done ' by this force during a displacement from x=0 to x=2.0 m .