For the line `(x-6)/(6)=(y+4)/(4)=(z-4)/(8),`

The distance,of the point (7,-2,11) from the line (x-6)/(1)=(y-4)/(0)=(z-8)/(3) along the line (x-5)/2=(y-1)/(-3)=(z-5)/(6) ,is :

Find the direction cosine of a line parallel to the line (2x-5)/(4)=(y+4)/(3)=(6-z)/(6)

Check whether the line (x-1)/(4)=(y+2)/(5)=(z-7)/(6) lines in the plane 3x+2y+z=6 .

The distance of the point (-2,4,-5) from the line (x+3)/(3)=(y-4)/(5)=(z+8)/(6) is

The distance of the point (-2, 4, -5) from the line (x +3)/(3)= (y - 4)/(5)= (z +8)/(6) is

The distance of the point (-2,4,-5) from the line (x+3)/(3)=(y-4)/(5)=(z+8)/(6) is

Find the direction cosines of a line parallel to the line : (x-5)/6=(y+4)/2=(7-z)/6

Find the distance between the parallel lines: (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-2)/(4)=(y-3)/(6)=(z-4)/(8)

Equations of the line through (4,-5,6) and perpendicular to the lines (x-11)/1=(y+6)/(-3) = (z-5)/0 and (x-1)/5 = (y-2)/2=(z-8)/11 are