The number of zeros at the end of `5^(10)!` is `(a^(10)-1)/(b)` then a+b is

The number of zeros at the end of 99^(100) - 1 is -

The number of zeros at the end of (101)^(11)-1 is

Number of zeroes at the end of 99^(1001)+1?

The number of zeros at the end of (108!) is (A) 25 (B) 16 (C) 21 (D) 10

Find the number of zeros in the product of 10!.

Number of zero's at the ends of prod _(n=5)^(30)(n)^(n+1) is :

The numbers 1, 3, 5, ….. 25 are multiplied together. The number of zeros at the right end of the product is 0 (b) 1 (c) 2 (d) 3

What is the number of zeros at the end of the product 5^(5)xx backslash10^(10)xx backslash15^(15)xx xx125^(125)?

The numbers 2,4,6,8,.....98,100 are multiplied together.The number of zeros at the end of the product must be 10 (b) 11 (c) 12 (d) 13

First 100 multiples of 10 i.e.10,20,30,...1000 are multiplied together.The number of zeros at the end of the product will be 100 (b) 111 (c) 124 (d) 125