`x=a sin2 theta(1+cos2 theta), y=b cos2 theta(1-cos2 theta)` then `(dy)/(dx)=`

If x= a sin 2theta (1+ cos 2theta) , y= b cos 2theta(1- cos 2theta) , then (dy)/(dx) =

If =a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta)x=a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta) and (dy)/(dx)=k tan theta then the value of k is

If x=a sin2 theta(1+cos2 theta) and y=b cos2 theta(1-cos2 theta), then prove that (dy)/(dx)=(b)/(a)tan theta

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If x=cos theta-cos2 theta,y=sin theta-sin2 theta then (dy)/(dx) is

if x=sin theta+theta cos theta,y=cos theta-theta sin theta then ((dy)/(dx))_(theta=(pi)/(2))=

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

x=sqrt(sin2 theta),y=sqrt(cos2 theta) then find (dy)/(dx)