`(tanx)/(cosx)`

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Prove that 1/(secx-tanx)+1/(secx+tanx)=2/(cosx)

int(tanx)/(1+cosx)dx=

Prove 1/(secx-tanx)-1/(cosx)=1/(cosx)-1/(secx+tanx)

int(tanx)/(log(cosx))dx=

y=(tanx)^(logx)+(cosx)^(sinx)

int(In(tanx))/(sinx cosx)dx " is equal to "

int_(0)^(pi)(tanx)/(secx+cosx)dx=