The dimensions of k in equation F = kx are

The dimensions of K in the equation W=1/2Kx^(2) is

The dimensions of K in the equation W=1/2Kx^(2) is

Find out the dimension of K in the equation, W= (1)/(2) Kx^(2) . Here x and W are the elongation and the potential energy respectively of a spring.

The dimension of omega in the expression y= Asin (omegat-kx) is

W = 1/2 kx^2 in this equation find out the dimension of k, where w = stored potential energy and x = eloxgation of the spring.

Force F is given by the equation F = X /Linear density Then dimension of X are

Find the condition on k for the equation kx^2+(k+2)x+(k+3)=0 to have real roots.

IF the product of the roots of the equation x^(2) - 3kx + 2 e^(2log k ) -1=0 is 17 then K=