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tan^(-1)1+tan^(-1)1/3=?...

`tan^(-1)1+tan^(-1)1/3=?`

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The numerical value of tan^(-1) 1+ tan^(-1) (1/2) + tan^(-1) (1/3) =_______.

The vlaue of tan^(-1)1/2+tan^(-1)1/3 is

The vlaue of tan^(-1)1/2+tan^(-1)1/3 is

Pove that i) tan^(-1)1/2+tan^(-1)2/11=tan^(-1)3/4 ii) tan^(-1)2/11+tan^(-1)7/24=tan^(-1)1/2 iii) tan^(-1)1+tan^(-1)1/2+tan^(-1)1/3=pi/2 iv) 2tan^(-1)1/3+tan^(-1)/17=pi/4 v) tan^(-1)2-tan^(-1)1=tan^(-1)1/3 vi) tan^(-1)+tan^(-1)2+tan^(-1)3=pi vii) tan^(-1)1/2+tan^(-1)1/5+tan^(-1)1/8=pi/4 viii) tan^(-1)1/4+tan^(-1)2/9=1/2tan^(-1)4/3

tan ^(-1) 1+tan ^(-1) 2+tan ^(-1) 3=

Prove that : tan^(-1) 1 + tan^(-1) 2 + tan^(-1) 3= pi = 2(tan^(-1) 1 + tan^(-1)((1)/(2)) + tan^(-1)( (1)/(3)))

Prove that : tan^(-1) 1 + tan^(-1) 2 + tan^(-1) 3= pi = 2(tan^(-1) 1 + tan^(-1)((1)/(2)) + tan^(-1)( (1)/(3)))