Five moles of hydrogen initially at STP is compressed adiabatically so that its temperature becomes 673K. The increase in internal energy of the gas, in kilo joule is (R=8.3J/molK, `gamma`=1.4 for diatomic gas)

Five moles of hydrogen initially at STP is compressed adiabatically so that its temperature becomes 673 K. The increase in internal energy of the gas , in kilo joule is (R= 8.3 J // mol-K, gamma = 1.4 for diatomic gas)

Five moles of hydrogen (gamma = 7//5) , initially at STP , is compressed adiabatically so that its temperature becomes 400^(@)C . The increase in the internal energy of the gas in kilojules is (R = 8.30 J//mol-K)

Five moles of hydrogen (gamma = 7//5) , initially at STP , is compressed adiabatically so that its temperature becomes 400^(@)C . The increase in the internal energy of the gas in kilojules is (R = 8.30 J//mol-K)

5 moles of Hydrogen (gamma =(7)/(5)) initially at STP are compressed adiabatically so that its temperature becomes 400^(@)C . The increase in the internal energy of the gas in kilo-joule is [R =8.30 J mol^(-1)K^(-1)]

Ten mole of hydrogen at N.T.P is compressed adiabatically so that it temperature becomes 400^(@)C . How much work is done on the gas? Also, Calculate the increase in internal energy of the gas. Take R=8.4J mol e^(-1)K^(-1) and gamma= 1.4 .

10 moles of hydrogen at N.T.p is compressed adiabatically so that its temperature becomes 400^@C . How much work in Joule is done on the gas ? What is the increase in internal energy of the gas. Given R=8.31"jmole"^-1k^-1 and gamma=1.4 .