AB,CD,PQ are perpendicular to BD. AB=x. CD=y and PQ=z, prove that `1/x+1/y=1/z`.

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

In the given figure AB || PQ || CD, AB=x, CD=y and PQ=z. Prove that 1/x+1/y=1/z

In the given figure, PA, QB and RC each is perpendicular to AC such that PA=x, RC=y, QB=z, AB=a, and BC=b Prove that (1)/(x)+(1)/(y)=(1)/(z)

In the given figure AB|PQ|CD, AB =x units ,CD=y units and PQ=z units,Prove that (1)/(x)+(1)/(y)=(1)/(z)

In the following figure, AB, CD and EF are perpendicular to the straight line BDF. If AB = x and, CD = z unit and EF = y unit, prove that : 1/x + 1/y = 1/z

In the adjoining figure , AB||CD||EF. prove that 1/x+1/y=1/z .

In the adjoining figure , AB||CD||EF. prove that 1/x+1/y=1/z .

In a right-angled triangle ABC, angleC = 90^(@) and CD is perpendicular to AB. If AB x CD = CA x CB, then 1/(CD^(2)) is equal to: