" Hान "sin alpha" cis "i" is "(tan35^(@))/(cot55^(@))+(cot78^(@))/(tan12^(@))-1

(tan 35^(@))/(cot 55^(@))+(cot 78^(@))/(tan 12^(@))=?

The value of ((tan35^(@))/(cot55^(@))+(cot78^(@))/(tan12^(@))) is

Evaluate the following : (tan35^(@))/(cot55^(@))+(cot78^(@))/(tan12^(@))-1

((tan35 ^ (@)) / (cot55 ^ (@))) + ((cos78 ^ (@)) / (sin (12 ^ (@)))) - 1

tan(55^(@)+x)=cot(35^(@)-x)

Prove that: (i) cos55^(@)sin 35^(@)+sin 55^(@)cos 35^(@)=1 (ii) (tan 72^(@))/(cot 18^(@))-(cot 72^(@))/(tan18^(@))=0 (iii) sec70^(@)sin 20^(@)+cosec 70^(@)cos 20^(@)=2

Evaluate the following: (i) (tan35^@)/(cot55^@)+(cot78^@)/(tan12^@)-1 (ii) (sec70^@)/(cos e c\ 20^@)+(sin59^@)/(cos31^@)

Evaluate: (cos 55^(@))/(sin 35^(@))+(cot 35^(@))/(tan 55^(@))

Simplify (cot 55^(@)cot35^(@)-1)/(cot55^(@)+cot35^(@))

Evaluate without using trigonometric tables. 2(("tan" 35^(@))/("cot" 55^(@)))^(2)+(("cot" 55^(@))/("tan" 35^(@)))^(2)-3(("sec" 40^(@))/("cosec" 50^(@)))