" 21."tan(3x+1)

The set of values of x for which ("tan" 3x- "tan" 2x)/(1+"tan" 3 x "tan" 2x) = 1 , is

tan^(- 1)x+tan^(- 1)\ (2x)/(1-x^2)=pi+tan^(- 1)\ (3x-x^3)/(1-3x^2),(x >0) is true if

Let |{:(tan^(-1)x, tan^(-1)2x, tan^(-1)3x), (tan^(-1)3x, tan^(-1)x, tan^(-1)2x), (tan^(-1)2x, tan^(-1)3x, tan^(-1)x):}|=0 , then the number of values of x satisfying the equation is

If tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)=tan^(-1)3x , then x =

Prove that : 2 tan^(-1) (1/3) +tan^(-1) (1/6) = tan^(-1) (22/21)

Solve: tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)= tan^(-1)3x.

Solve tan^(-1)(x-1) +tan^(-1) x +tan^(-1)(x+1)= tan^(-1)(3x) .

Solve: tan ^ (- 1) (x-1) + tan ^ (- 1) x + tan ^ (- 1) (x + 1) = tan ^ (- 1) 3x

Solve (tan 3x - tan 2x)/(1+tan 3x tan 2x)=1 .

Solve (tan 3x - tan 2x)/(1+tan 3x tan 2x)=1 .