[" For the plane the cosines of the normal to "],[[" (i) "2x+3y-z=5," (ii) "z=3," (iii) "3y+5=0]]

For each of the following planes, find the direction cosines of the normal to the plane and the distance of the plane from the origin: i) 2x+3y-z=5 , ii) z=3 , iii) 3y+5=0 .

Find the direction cosines of the normal to the plane 2x+3y-z=4 .

The directions cosines of the normal to the plane 2x-y +2z =3 are

Direction cosines of the normal to the plane: 2x-3y+4z-6=0 are :

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

The d.c.'s of the normal to the plane 2x + 3y – 6z + 5 = 0 are

In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin. (a) z=2 (b) x+y+z=1 (c) 2x+3y-z=5 (b) 5y+8=0