" 19."sin^(n)x

If sin x + "cosec"x=2 , then, for all n in N , the value of: sin^(n)x + "cosec"^(n)x=

If sin+cosecx = 2, then sin^(n)x +cosec^(n) x is equal to

For n in N, int_(0)^(2pi) (x sin^(2n)x)/(sin^(2n) x + cos^(2n) x) dx=

The general solution of the equation (1-sin x+...+(-1)^(n)sin^(n)x+...)/(1+sin x+......+sin^(n)x+...)=(1-cos2x)/(1+cos2x)

If for n obtained in above question sin^(n) A= x then sin A sin 2A sin 3A sin 4A is a polynomial in x of degree

If sin x + cos x = 2 , then the value of sin^(n)x + cos^(n)x will be-

If sin x+cosec x=2 , then sin ^(n) x+cosec^(n) x=