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" (10) "xy(dy)/(dx)=x^(2)+2y^(2),y(1)=0...

" (10) "xy(dy)/(dx)=x^(2)+2y^(2),y(1)=0

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Particular solution of the differential equation xy(dy)/(dx)=x^(2)+2y^(2),y(1)=0, is

(dy)/(dx)=xy+2y+x+2

(dy)/(dx)=(x^2y+y)/(xy^2+x)

(dy)/(dx)=(y^(2)-x)/(xy+y)

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

(dy)/(dx) = (2xy)/(x^(2)-1-2y)