`PCl_(5)` on heating dissociates to `PCl _(3) and Cl _(3)` because :

PCl_(5) on heating dissociates to PCl _(3) and Cl _(2) because :

When PCl_(5) is heated, it dissociates into PCl_(3) and Cl_(2) . The vapour density of the gas mixture at 200^(@)C and at 250^(@)C is 70 and 58 , respectively. Find the degree dissociation at two temperatures.

When PCl_(5) is heated, it dissociates into PCl_(3) and Cl_(2) . The vapour density of the gas mixture at 200^(@)C and at 250^(@)C is 70 and 58 , respectively. Find the degree dissociation at two temperatures.

Why PCl_(5) dissociates to give PCl_(3) and Cl_(2) ?

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :

1.5 mol of PCl_(5) are heated at constant temperature in a closed vessel of 4 L capacity. At the equilibrium point, PCl_(5) is 35% dissociated into PCl_(3) and Cl_(2) . Calculate the equilibrium constant.

1.5 mol of PCl_(5) are heated at constant temperature in a closed vessel of 4 L capacity. At the equilibrium point, PCl_(5) is 35% dissociated into PCl_(3) and Cl_(2) . Calculate the equilibrium constant.

PCl_(5) is 50% dissociated into PCl_(3) and Cl_(2) at 1 atmosphere pressure. It will be 40% dissociated at: