" 6."(x+5)^(2)+(y-3)^(2)=36

Describe the graph of the set of points (x,y,z) where (x-6)^(2) +(y+3)^(2) +(z-2)^(2)=36

24x ^(3) - 36x ^(2)y

Factorize :12x^(3)y^(3)+16x^(2)y^(5)-4x^(5)y^(2)18a^(3)b^(2)+36ab^(4)-24a^(2)b^(3)

For all values of a and b, show that the circle (x - 2) (x - 2 + a) + (y + 3) (y +3 + b) = 36 bisectsthe circumference of the circle. (x-2)^2 + (y + 3)^2 = 36.

The point of intersection of the lines (x-5)/(3) = (y-7)/(-1) = (z+2)/(1) and (x+3)/(-36) = (y-3)/(2) = (z-6)/(4) is

The point of intersection of the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1) and (x+3)/(-36)=(y-3)/(2)=(z-6)/(4) is (A) (21,(5)/(3),(10)/(3))(B)(2,10,4)(C)(-3,3,6)(D)(5,7,-2)

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)