(1+cos theta-sin^(2)theta)/(sin theta(1+cos theta))=cot theta

(sin 2 theta)/(1-cos 2 theta)=cot theta

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

(2 sin theta*cos theta - cos theta)/(1-sin theta+sin^2 theta-cos^2 theta) = cot theta

prove that (cos theta)/(1-tan theta)+(sin theta)/(1-cot theta)=cos theta+sin theta

cos theta/(1+sin theta)=(1-sin theta)/cos theta

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

Prove that: (a) (sin 2 theta)/(1+cos 2 theta)=tan theta (b) (1+sin 2 theta+2theta)/(1+sin2 theta-cos 2 theta)=cot theta

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then