" (1) "int(x^(3)sin(tan^(-1)x^(4)))/(1+x^(8))dx

Evaluate int(4x^(3)sin(tan^(-1)(x^(4))))/(1+x^(8))dx

int(x^(3)[tan^(-1)(x^(4))]^(2))/(1+x^(8))dx=

(x^3sin(tan^(- 1)x^4))/(1+x^8)

int x^(3)(tan^(-1)x)dx

int(x tan^(-1)x^(2))/(1+x^(4))dx

int(x^(3)sin[tan^(-1)(x^(4))])/(1+x^(8))dx is equal to : a) 1/4cos[tan^(-1)(x^(4))]+c b) 1/4sin[tan^(-1)(x^(4))]+c c) -1/4cos[tan^(-1)(x^(4))]+c d) 1/4sec^(-1)[tan^(-1)(x^(4))]+c

int (sin (tan^(-1)x)dx)/(1+x^(2))

int (sin (2tan^(-1)x))/((1+x^(2)))dx.